what are the solutions to 6x^2 = 18x

Question

mathstudent55 · Answer

Subtract 18x to left side.
Then divide both sides by 6.
Then factor out x.
Then set both factors equal to zero and solve each one.

anonymous · Answer

How am I suppose to divide 6 and 0?

zehanz · Answer

This is an equation of the form $a\cdot b=a\cdot c$ .
Such an equation can be split up in two parts: 

1. $a=0$  (if a=0, then you get the statement 0=0, which is true)
2. $b=c$  (if a is not zero, divide both sides by a, leaving b=c).

Here you can split up in

$6x \cdot x=6x \cdot 3$, so a=6x, b=x and c=3.

So the equation becomes:

1. $6x=0$  Not difficult to solve...
2. $x=3$    Hey, a solution!

mathstudent55 · Answer

Follow me. Doone step at a time and show your work.
6x^2 = 18x
Subtract 18x from both sides.

anonymous · Answer

6x^2 - 18 = 0

mathstudent55 · Answer

Don't lose the x with the 18x

mathstudent55 · Answer

It shoudl readd 
6x^2 - 18x = 0
Now divide both sides by 6. Whatdo you get?