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Mathematics 15 Online
OpenStudy (anonymous):

Help?! L.A. = http://tinypic.com/r/rv8t50/6

OpenStudy (anonymous):

L.A. = Lateral Area

OpenStudy (anonymous):

whats it?

OpenStudy (mertsj):

There are 5 faces: 2 triangles and 3 rectangles. Are you with me on that?

OpenStudy (anonymous):

yes

OpenStudy (mertsj):

But we want only the lateral area which is the area of the 3 rectangular sides. Do you agree?

OpenStudy (anonymous):

yes

OpenStudy (mertsj):

Now the left rectangle has base 4 and height 8 so its area is...

OpenStudy (anonymous):

32

OpenStudy (mertsj):

The right rectangle has base 6 and height 8 so its area is....

OpenStudy (anonymous):

48

OpenStudy (mertsj):

The front rectangle has height 8 but we have to use the Pythagorean Theorem to find its base. Can you do that?

OpenStudy (anonymous):

what exactly is the formula of the Pythagorean Theorem?

OpenStudy (mertsj):

a^2 + b^2 = c^2 For find the hypotenuse of a right triangle.

OpenStudy (mertsj):

*finding

OpenStudy (anonymous):

okay... I'm not sure what exactly to plug in a^2 + b^2 = c^2

OpenStudy (mertsj):

|dw:1364254015037:dw|

OpenStudy (mertsj):

4^2+6^2=c^2

OpenStudy (anonymous):

8 + 36 = c^2

OpenStudy (mertsj):

No. 4^2=16

OpenStudy (anonymous):

oh right, sorry ...

OpenStudy (anonymous):

16 + 36 = c^2

OpenStudy (mertsj):

\[c=\sqrt{52}=2\sqrt{13}\]

OpenStudy (mertsj):

So the front rectangle has base 2sqrt13 and height 8 so it's area is...

OpenStudy (anonymous):

57 ?

OpenStudy (mertsj):

|dw:1364254313127:dw|

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