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OpenStudy (anonymous):
Help?!
L.A. =
http://tinypic.com/r/rv8t50/6
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OpenStudy (anonymous):
L.A. = Lateral Area
OpenStudy (anonymous):
whats it?
OpenStudy (mertsj):
There are 5 faces: 2 triangles and 3 rectangles.
Are you with me on that?
OpenStudy (anonymous):
yes
OpenStudy (mertsj):
But we want only the lateral area which is the area of the 3 rectangular sides. Do you agree?
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OpenStudy (anonymous):
yes
OpenStudy (mertsj):
Now the left rectangle has base 4 and height 8 so its area is...
OpenStudy (anonymous):
32
OpenStudy (mertsj):
The right rectangle has base 6 and height 8 so its area is....
OpenStudy (anonymous):
48
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OpenStudy (mertsj):
The front rectangle has height 8 but we have to use the Pythagorean Theorem to find its base. Can you do that?
OpenStudy (anonymous):
what exactly is the formula of the Pythagorean Theorem?
OpenStudy (mertsj):
a^2 + b^2 = c^2 For find the hypotenuse of a right triangle.
OpenStudy (mertsj):
*finding
OpenStudy (anonymous):
okay... I'm not sure what exactly to plug in a^2 + b^2 = c^2
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OpenStudy (mertsj):
|dw:1364254015037:dw|
OpenStudy (mertsj):
4^2+6^2=c^2
OpenStudy (anonymous):
8 + 36 = c^2
OpenStudy (mertsj):
No. 4^2=16
OpenStudy (anonymous):
oh right, sorry ...
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OpenStudy (anonymous):
16 + 36 = c^2
OpenStudy (mertsj):
\[c=\sqrt{52}=2\sqrt{13}\]
OpenStudy (mertsj):
So the front rectangle has base 2sqrt13 and height 8 so it's area is...
OpenStudy (anonymous):
57 ?
OpenStudy (mertsj):
|dw:1364254313127:dw|
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