Question

Factor by grouping.
18b^2+25b-3

Answer 1

Why? Anyway...

18b^2 + 25b - 3 = 18b^2 - 2b + 27b - 3

Now what?

Answer 2

\[18b^2+25b-3\]multiply \(18\) and \(-3\) and see which factors add up to \(25\)
in this case the 2 factors that work are \(27\) and \(-2\)
write the middle term, \(25b\) split up as \(27b-2b\)
\[18b^2+27b-2b-3\]group these (add parenthesis):\[(18b^2+27b)-(2b+3)\]factor out the GCF:\[9b(2b+3)-1(2b+3)\]rearrange that and write:\[(9b-1)(2b+3)\]tada! :D

Answer 3

I'm a little delighted that we did it differently.

Answer 4

LOL