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Physics 12 Online
OpenStudy (anonymous):

If P(A|B) = P(A) then we know A and B are independent P(A∩B) = P(A)P(B) P(A∪B) = P(A)+P(B) Both A and B Both A and C

OpenStudy (kropot72):

Option C \[P(A \cup B)=P(A)+P(B)\] applies to mutually exclusive events and is the probability of A or B occurring. If two events are mutually exclusive, it is impossible for them to happen together.

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