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OpenStudy (anonymous):
In a simple way the graph is ought to be in the form of\[ y = ax^2 + bx + c\] right.
OpenStudy (anonymous):
answer is B
OpenStudy (anonymous):
sorry \[y = a(x – h)^2 + k\]
OpenStudy (anonymous):
And the properties say:
1.When h is positive the graph shifts right; when h is negative the graph shifts left.
2.When k is positive the graph shifts up; when k is negative the graph shifts down.
3. The vertex is (h, k) and the axis of symmetry is the line x = h.
OpenStudy (anonymous):
it obeys the function, y=1 then x=+2 or -2 and when y=4 x=+4 or -4
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OpenStudy (anonymous):
The graph is <2,1>
Use vertex form
y = a(x – h)2 + k
Substitute h = 2 and k = 1
y = a(x – 2)2 + 1
The equation of the parabola is
y = )y=x^2/4
OpenStudy (anonymous):
hope it helps
OpenStudy (anonymous):
IT HELPED ALOT I WENT STEP BY STEP TO SOLVE IT. THANK YOU!!!