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Mathematics 16 Online
OpenStudy (anonymous):

PLEASE HELP ME!!!! Use the graph to write an equation for the parabola?

OpenStudy (anonymous):

OpenStudy (anonymous):

Graph??

OpenStudy (anonymous):

above! ^

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

choices are: A)y= -x^2/4 B)y=x^2/4 C)y=x^2/2 D)y=2x^2

OpenStudy (anonymous):

In a simple way the graph is ought to be in the form of\[ y = ax^2 + bx + c\] right.

OpenStudy (anonymous):

answer is B

OpenStudy (anonymous):

sorry \[y = a(x – h)^2 + k\]

OpenStudy (anonymous):

And the properties say: 1.When h is positive the graph shifts right; when h is negative the graph shifts left. 2.When k is positive the graph shifts up; when k is negative the graph shifts down. 3. The vertex is (h, k) and the axis of symmetry is the line x = h.

OpenStudy (anonymous):

it obeys the function, y=1 then x=+2 or -2 and when y=4 x=+4 or -4

OpenStudy (anonymous):

The graph is <2,1> Use vertex form y = a(x – h)2 + k Substitute h = 2 and k = 1 y = a(x – 2)2 + 1 The equation of the parabola is y = )y=x^2/4

OpenStudy (anonymous):

hope it helps

OpenStudy (anonymous):

IT HELPED ALOT I WENT STEP BY STEP TO SOLVE IT. THANK YOU!!!

OpenStudy (anonymous):

No Problem:)

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