PLEASE HELP!!!!! If f(3)=1.8 and f(4)=-3.2, use linear interpolation to approximate f(3.6)
i guess you are being asked to find the equation of the line between the points \((3,1.8)\) and \(( 4,-3.2)\) do you know how to do that?
you need the slope of the line \[\frac{-3.2-1.8}{4-3}=-5\]
yes i do, but what do you do after you find the equation of the line?
replace \(x\) by \(3.6\)
oh okay and then y = f(3.6)?
what answer did you get?
i didn't do it, but i can. give me a second
thanks! :)
no it isn't line is \(y=-5x+16.8\)
then \(-5\times 3.6+16.8=-1.2\)
okay i got the same answer! thanks abillion!!!!
yw
can you help me with another porblem?
sure
okay here it is, is -3/2 a root of 3x^3 -5x^2-2=0
dunno but i can use a calculator to see if \[3(\frac{-3}{2})^3-5(-\frac{3}{2})^2-2=0\]
okay
i will try tht
http://www.wolframalpha.com/input/?i=3%28 \frac{-3}{2}%29^3-5%28-\frac{3}{2}%29^2-2%3D0
i used that calc and it does not equal zero. so i guess it is not a root. lol
this one might be clearer, but it does not seem to be zero http://www.wolframalpha.com/input/?i=3%28-3%2F2%29^3-5%28-3%2F2%29^2-2
and one last question, If P is a polynomial function, and P(1)=P(4)=6, could P have a zero between 1 and 4?
why not?
that is the answer that I got a well. you are such a help to me!!!!
glad to help
I am not sure. lol so the answer is yes?
yes, it could have zero between 1 and 4
okay. thank you!
yw
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