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Okay so we're doing Quadratic equations and i'm trying to find the vertex. i have the AOS, but how do i find the vertex if 'x' is in the 'a' position? the problem is y=x^2+6x-6
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what did you get for the axis of symmetry
-3
how did you get - 3?
that's the x coordinate of the vertex, plug that into the equation to find y
y=x^2+6x-6 y=(-3)^2+6(-3)-6 y = ??
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okay i got -12
close, but no
okay, i dont know where i went wrong
y=(-3)^2+6(-3)-6 y=9+6(-3)-6 y=9-18-6 y = ???
oh..wow okay -15?
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yep
okay thanks
np
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