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Simplify: (5x^8)(5x^7)/15x^4
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\[5x ^{19}/3\\]
thanks :) can you help me with another one?
Sure (;
\[(\frac{6y^7 }{2y^2 })^{-4}\]
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(6y^7/2y^2)^-4
\[\frac{ 1 }{ 81y ^{36} }\]
its not the right answer :(
Thats aa 36 BTW
i know. i put it in but its the wrong answer
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Are You Sure You Told Me The Correct Problem ? Did You Leave Something Out?
i didnt leave anything out. its just really confusing.
\[(\frac{6y^7}{2y^2})^{-4}=(\frac{2y^2}{6y^7})^4=(\frac{1}{3y^5})^4=\frac{1}{81y ^{20}}\]
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