Using kite DEFG, find the measure of ∡E. 108° 18° 36° 216° http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0502_06/image0024e36f3fb.gif
I don't get how to do this like what equation
since this is a kite, the sum of all the interior angles is 360. you also know that angle E and G are equal by symmetry...
D + E + F + G = 360 degrees E = G since you're given D and F, substitute the values into the equation...
divide the kite into two triangles first will be triangle DEG and the other is triangle EFG both these triangle are isosceles now the sum of all angles in a triangle is 180 for triangle DEG consider the other two angle x 106+x+x=180 106+2x=180 2x=180-106 x=74/2 x=37 this gives you one part of angle E now for the second part consider triangle EFG 38+x+x=180 38+2x=180 2x=180-38 x=142/2 x=71 now total angle E is equal to sum of the two parts i.e. <E= 37+71 = 108 degree so option B is the answer :)
Yeah I got that thank you!
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