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Mathematics 11 Online
OpenStudy (anonymous):

Choose the function whose graph is given by (graph inside!) A. y = 3cos(1/4x) B. y = -3cos(4x) C. y = 3cos(4x) D. y = 3cos(pi/2x) ***still confused.. so it's a different graph now :/

OpenStudy (anonymous):

graph :/

OpenStudy (mertsj):

This is obviously a well behaved cosine except that its amplitude is not 1 and it's period is not 2pi

OpenStudy (mathstudent55):

The cosine function goes from y = -1 to y = 1. This has a vertical stretch of 3, so that indicates y = 3*cos(x)

OpenStudy (mertsj):

Take her through the period calculation mathstudent

OpenStudy (mathstudent55):

Now you need to deal with the "sqeeze" in x

OpenStudy (anonymous):

okay... so we can narrow it down now right? it HAS to be a positive 3cos right? which leads us to either C. y = 3cos(4x) or D. y = 3cos(pi/2x) right?? am i getting that part?? and what do u mean my "squeeze" ?? :/

OpenStudy (mathstudent55):

Yes, it has to be positive 3

OpenStudy (anonymous):

okay :) what do we do next?

OpenStudy (mathstudent55):

Normally the period of the cosine function is 2pi. That means it takes 2pi in x to see the entire look of the function. More than 2pi will create a repetition of the values of the function.

OpenStudy (anonymous):

okay.. but this one doesn't have a period of 2pi right?

OpenStudy (mathstudent55):

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