Write the equation of the line given the slope and the y-intercept. m = 5, y-intercept (0, -3)
Use the fact that the equation of any line in slope intercept form is y = mx+b
So if say the slope was 17 and the y-intercept was (0,8), then y = mx+b y = 17x + b y = 17x + 8 This is NOT the answer as it's just an example
y=5x+-3 ?
good, and that simplifies to y = 5x - 3
I should have pointed out that m is the slope and b is the y-intercept (which is the point (0,b)) But I'm sure you've already figured that part out by now
So then my answer would be y=5x-3 ?
yes correct
Wow, that makes sense. Thanks @jim_thompson5910 !
glad to be of help
@jim_thompson5910 I also have a similar problem if you could help....
Write the equation of the line given the slope and a point on the line. in slope-intercept form, m = -4, point (1, -3)
Would it be y=-4+-3 ?
no the trick used above only works if the point looks like (0, ???) where you replace the ??? with any number
So the trick works if the line goes through (0,6) or (0,19)....but does NOT work for (1,-3)
you have to do this
y = mx + b y = -4x + b ... plug in m = -4 -3 = -4(1) + b .... plug in x = 1 and y = -3 (from the point (1,-3)) -3 = -4 + b ... multiply I'll let you finish and solve for b
-3=-4+-3 ?
if you have -3 = -4 + b how would you isolate b
add four to both sides?
1=b ?
very good
b = 1
so m = -4 and b = 1
which means y = mx+b turns into y = -4x + 1
OR you could always use the point slope formula.....(it simplifys to y=mx + b) m = -4, point (1, -3) y - y1 = m(x - x1) you have a point...(1, -3) and a slope (-4) in this equation...m is slope so y - (-3) = -4(x - 1) y + 3 = -4x + 4 finish that simplification :)
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