Question

Discontinuities of Rational Functions

Answer 1

\[f(x) = \frac{ 2x ^{2} + 5x - 12 }{ x+4 } \]

Answer 2

I solved and ended up with x = 3 as the zero?

Answer 3

Work:
\[f(x) = \frac{ (2x ^{2} + 8x)(x+4) }{ (x+4) }\]

Answer 4

so f(x) can't equal -4

Answer 5

\[x\ne4\]
when it does, you cannot cancel off the two terms and you have a discontinuity there.

Answer 6

discontinuity because, the limit exists at \(x\to-4\), however, the function value does not.

Answer 7

Wait, never mind, I made a mistake in Geogebra.., gr >_< I was right. Thanks, Electro!

Answer 8

np.