Question

10. Challenge: Graph the equation with a diameter that has endpoints at (2, 2) and (-4, -2). Label the center and at least four points on the circle. Write the equation of the circle.

Answer 1

@jim_thompson5910

Answer 2

same idea as last time

Answer 3

find the midpoint to get the center

then find the distance from center to either endpoint to get the radius

Answer 4

can you set it up :) its my last question n i'll finally be done :D

Answer 5

you add up the corresponding coordinates, then divide by 2 to get the midpoint

Answer 6

what do you get for the midpoint

Answer 7

idk

Answer 8

ok what do you get when you add up the x coordinates

Answer 9

can you set it for me? @jim_thompson5910

Answer 10

2 + (-4) = ??

Answer 11

-2

Answer 12

divide that in half

Answer 13

2/2=1

Answer 14

-2/2 = -1

Answer 15

so the x coordinate of the center is -1

Answer 16

now what about y?

Answer 17

add up the y coordinates

Answer 18

2+-2?

Answer 19

@jim_thompson5910

Answer 20

that adds to what

Answer 21

0

Answer 22

then you divide that in half to get 0/2 = 0

Answer 23

So the center is (-1,0)

Answer 24

now you use this center, and another point, to find the radius

Answer 25

@jim_thompson5910 so whats my radius?

Answer 26

use the distance formula

d = sqrt((x2-x1)^2+(y2-y1)^2)

to find the distance from (-1,0) to (2, 2)

Answer 27

d-2--1^2 2-0^2

Answer 28

@jim_thompson5910

Answer 29

d = sqrt((x2-x1)^2+(y2-y1)^2)


d = sqrt((2-(-1))^2+( 2-0)^2)


d = sqrt((2+1)^2+( 2-0)^2)


d = sqrt((3)^2+(2)^2)


d = ???

Answer 30

9 +4
13

Answer 31

so the radius is \[\Large \sqrt{13}\] units

Answer 32

thts it?

Answer 33

yes

Answer 34

thank you for all your help!! :D

Answer 35

yw