An amateur rocketry club is holding a competition. There is cloud cover at 1000 ft. If a rocket is launched with a velocity of 315 ft/s, use the function h(t)= -16t + vt + h0 to determine how long the rocket is out of sight?

Question

anonymous · Answer

Quadratic formula word problems.

anonymous · Answer

i am pretty sure your equation is wrong the the first term is squared.
h(t)= -16t^2 + vt + h0   <-- fixed
v=315 ft/s

plug in v into the equations

h(t)=-16t^2 + (315)t + h0     I am sure h0 means the height of where the rocket is at which is 0. AKA the original spot the launching pad.

1000=-16t^2 + (315)t    set height to 0  and solve for t.  the answer will be in seconds. Cand you solve for t?

anonymous · Answer

Once you solved you'll get to solutions for t   t1 and t2 because it is a quadratic you will most likely get 2 solutions to the equation. 

then answer is just t1-t2.   or t2-t1 whichever gets you the highest  number.