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microwave ovens emit microwave energy with a wavelength of 12.7 cm. what is the energy of exactly one photon of this microwave radiation?
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\[E=hc/\lambda \] \[(6.626*10^-34 J*s)(3.00*10^8 m/s)/.127m\] =1.57*10^24 J
Correct Answer- 1.57*10^-24 J
Should be (6.626*10^-34 J*s)
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