Question

Please help!

Answer 1

You can put that 2x+y in the denominator and then factorize all.
Consider 4x^2 = (2x)^2
And 8x^3 = (2x)^3

The use the identities of a^2-b^2 and a^3-b^3

Answer 2

@Juarismi would C be correct?

Answer 3

I don´t think so.

Factorizing propertly almost all the terms cancel each others.

Remember :
\[a^2-b^2=(a+b)(a-b)\]
\[a^3-b^3=(a-b)(a^2+ab +b^2)\]

Answer 4

@Juarismi I got 1/ (4x^2 + 2xy +y^2)

Answer 5

Congrats, that is the answer.

Answer 6

Thank you!!