Question

A solution to the compound inequality 16 > 4 - 3x > -11 is provided below. Choose the statement that is true about the given solution.


16 > 4 - 3x and 4 - 3x > -11

Line 1

12 > -3x and -3x > -15

Line 2

-4 > x and x > 5

Line 3

There is a mistake in line # 1.

There is a mistake in line # 2.

There is a mistake in line # 3.

There are no mistakes, the solution is correct.

Answer 1

@dmezzullo

Answer 2

well
16 > 4 - 3x is 1st
4 - 3x > -11 2nd
does that make easier

Answer 3

no

Answer 4

well

Answer 5

go through the steps and look at the math done, see if there are any subtraction, multiplication, or division problems with their work...if not then then its D. if so pick your answer :)

Answer 6

okay thank you

Answer 7

tell me what you come up with!

Answer 8

b?

Answer 9

correct :D

Answer 10

hmm
16 > 4 - 3x
16-4>-3x
12>-3x........... 1st line equation
further
12/-3>x
-4>x...............2nd of the line equation

Answer 11

yay!!

Answer 12

good job :D

Answer 13

:/
its D

Answer 14

no its not? on line two they divide by a negative but dont flip the signs..

Answer 15

-4 > x and x > 5
is wrong u wanna say?

Answer 16

yes, since they divided by a -3 the ">" should flip and be "<"

Answer 17

r u sure :)

Answer 18

mhmm..

Answer 19

:P

Answer 20

@electrokid do the signs flip?is she correct?

Answer 21

@aajugdar i have been doing these problems for 5+ years, the signs flip.

Answer 22

@aajugdar, @Hope_nicole is correct. The signs flip when you multiply or divide an in-equality by a negative number.

Answer 23

cant beat the experience
oops

Answer 24

this is awkward
i owe an apology

Answer 25

sorry :D

Answer 26

you're fine :) you were just making sure I was helping correctly .

Answer 27

@aajugdar and @Hope_nicole medals to both
and the asker for keeping silent throughout. Dont even know if she understood this!

Answer 28

i always wonder that abt every1 to whom i answer