Question

Can some one explain this to me? need to figure how many real-number solutions there are.
–7x² + 6x + 3 = 0

*one solution
*two solutions
*no solutions
*infinitely many solutions

Answer 1

when $$\Delta =b^2-4ac$$ of$$ax^2+bx+c=0$$
there is one solution when $$\Delta=0$$ There are two solutions when,$$\Delta>0$$,and there is no 'real' solution when,
$$\Delta<0$$
Use this property

Answer 2

@BAdhi ur intuition is right but when delta is zero then there are two solutions but two solutions are same.

Answer 3

According to Fundamental theorem of algebra, nth degree polynomial wil have n roots , where roots may be real or may be complex

Answer 4

for the given problem , as delta is greater than zero, two solns are there/