Question

Which function's graph has a period of 2?
y=cos(x-pi/2)
y=3cos pi x
y=2 sin 3x
y=-4 sin 2x

Answer 1

The function takes the form
\[\huge y=a\sin(bx+c)+d\]in general. By the way, it doesn't matter here, if sin is replaced by cos. The period is given by this formula
\[\huge \frac{2\pi}{b}\]

Answer 2

so it would be y= 2 sin 3x

Answer 3

no it's not y = 2*sin(3x)

Answer 4

that has a period of

T = 2pi/B

T = 2pi/3

Answer 5

y=3cos pi x? 2 pi/pi

Answer 6

Yes, that's right ^.^

Answer 7

\[\Large \frac{2\pi}{\pi}=2\]

Answer 8

thank you for explaining how to do it

Answer 9

y= -4 sin pi x