A bag has 2 green marbles, 3 red marbles, and 3 yellow marbles. What is the probability that you pick a green marble, do not replace it, and pick a yellow marble?
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jimthompson5910 (jim_thompson5910):
how many green marbles are there
OpenStudy (anonymous):
2
jimthompson5910 (jim_thompson5910):
how many total
OpenStudy (anonymous):
8
jimthompson5910 (jim_thompson5910):
so if you were just picking one marble, then the probability of picking green is 2/8
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jimthompson5910 (jim_thompson5910):
but we're picking 2 marbles
and we are NOT putting the first one picked back in
jimthompson5910 (jim_thompson5910):
so after you pick the first one, the total drops from 8 to 7
So the probability of picking yellow on the second selection is 3/7 (since there are 3 yellow out of 7 total left)
jimthompson5910 (jim_thompson5910):
Multiply these two together to get
(2/8)*(3/7) = ???
OpenStudy (anonymous):
so would it be
3/28
jimthompson5910 (jim_thompson5910):
(2/8)*(3/7) = (2*3)/(8*7)
(2/8)*(3/7) = 6/56
(2/8)*(3/7) = 3/28
So you are 100% correct
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