Question

HEEEEEEELP PLEASE!

Answer 1

E,F,G,H are there midpoints ,yes ?

Answer 2

I guess they are @jhonyy9

Answer 3

and BC = BA and DC = DA ,yes ?

Answer 4

@jhonyy9 yes

Answer 5

so if you rotate 90 degree this rectangle ,how do you think what you get what is this rectangle when you know that the adjacent sides are equales and again how you can seeing that the opposite sides are parallelles ?

Answer 6

That the sum of the measures are equal

Answer 7

no i have thought that you get from this rectangle a rhombus

ok ?

Answer 8

Aaa ok ok

Answer 9

so and what you know again from the diagonales of a rhombus ?

Answer 10

We can calculate the properties

Answer 11

so halved ,yes ?

Answer 12

yes

Answer 13

let O the intersection point of AC and BD
so in this way you can calculi now how many long ,what is the length of their half part ,yes ?

Answer 14

the half part of AC and BD

ok ?

Answer 15

AC = 13 and BD = 26

Answer 16

half of AC = 6.5

Answer 17

Half of BD = 13

Answer 18

yes ,right

so now there are triangles BOC ,BOA, DOC and DOA

yes ?

so what you know ,what property you know from these triangles ,looking the angles O_1,O_2,O_3 and O_4 this sre the centrale angles with how many degree ?

Answer 19

90 degrees ?

Answer 20

yes right

so than there are 4 right triangles from what you know their laterale sides

ye ?

Answer 21

Yes

Answer 22

using pythagora what you can easy calculi for these 4 triangles ?

Answer 23

I don't know :(

Answer 24

why ? this is easy

if you know the lenght of two sides of a right triangle using pythagora how you can calculi the hypothenuse ?

Answer 25

c^2 = a^2 + b^2

Answer 26

yes right

Answer 27

so using this you can calculi easy these 4 hypothenuses

yes ?

Answer 28

yes

Answer 29

can you calculi now here ?

Answer 30

is BOC = 13 ?

Answer 31

no

you need calculi the laterale sides what are hypotenuses of these right triangles

Answer 32

I have no idea :( sorry for bothering you ... you can give up if you want

Answer 33

so you have wrote little above that

a^2 = b^2 +c^2 where a is hypothenuse and b,c the lateral sides

yes ?

Answer 34

yes

Answer 35

so you know the langth of OA OB OC and OD

using pythagora you can calculi the length of lateral sides

Answer 36

lateralé sides what are AB AD BC and DC

Answer 37

you dont like calculi it ?

Answer 38

No I am sorry my brain is not functioning I am having a massive headache

Answer 39

I cant seem to function, I am so sorry:(

Answer 40

do you like i help you ?

Answer 41

AO = 6,5
BO = 13

Answer 42

so than

BA^2 = AO^2 + BO^2
BA^2 = 42,25 + 169

BA^2 = 211,25

BA = sqrt(211,25)

BA = 14,5

so what mean that BC = 14,5 too

Answer 43

AD=DC so their langth will be the same 14,5

yes ?

Answer 44

Yes thank you for helping me !!! a lot!!! I am such a loser :(

Answer 45

yes

Answer 46

@jhonyy9

Answer 47

you can writing again the rationalitie of sides

AB / AH = AC / EH

14,5 / 7,25 = 13 / EH

cross multiplie

14,5*EH = 13 * 7,25

14,5*EH = 94,25

EH = 94,25 / 14,5 = 6,5

EH = 6,5 what mean that is a haéf part of 13 what is a half part of 26

yes ?

Answer 48

Yes! Yes I understand what you did there

Answer 49

so EH = FG = 6,5

and EF = HG = 26/2 = 13

can you calculi now the perimeter of this rectangle ? this is easy

Answer 50

P = 2L + 2W is the formula right

Answer 51

yes

Answer 52

So length is CA and width is BD?

Answer 53

no

Answer 54

you need calculi the perimeter of this rectangle

Answer 55

this perimeter you will get assuming the length of EH ,EF and HG ,FG

OK ?

Answer 56

ok

Answer 57

so the result for perimeter will be ?

Answer 58

so length is EH and FG and width is EF and HG

Answer 59

so will be 6,5 +6,5 + 13 + 13 = ?

Answer 60

39

Answer 61

yes right

so was difficile ?

Answer 62

Well without your help I would have done nothing!

Answer 63

So it is all thanks to you :)

Answer 64

was my pleasure

good luck

bye

yw

Answer 65

thank you a lot!