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if \[\log_{b}3=0.23 an \log_{b}8=0.71, find \log_{b}24 \]
round to the nearest thousanths
@jim_thompson5910
@timo86m
yes i know that but its not the answer
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using what HawkCrimson is saying you do this log(24) = log(8*3) log(24) = log(8) + log(3) log(24) = 0.71 + 0.23 log(24) = 0.94 All logs above are base b
i got log(24) as 1.380
that's if the base is 10
but in this case, the base is b and we don't know what b is
ohhhh, so rounded what would it be
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just 0.94, it's already rounded so to speak
if you had more than 3 decimal digits, then you would need to round
ok(: than k you
yw
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