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find the vertex. y=-x^2+2x+4
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Complete the square! y = -(x^2 - 2x + ____) + 4 + ____
what do you mean
I would do -b/2a
So, a=-1,b=2, c=4, now you are putting -b/2a -2/-2=1, and then you will plug the value of 1 to find the corresponding y coordinate
\[x^2+ 2x+4\\ ( x^2+ 2x )+4\\ x^2+ 2x+( \frac{2}{2})^2 ) + 4 - ( \frac{2}{2})^2 ) \\ ( x + 1)^2 + 3 \]
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\[ \text{ So, here, the Vertex} = ( -1,3) \]
luis its -x^2
If you Complete the Square, like Luis_Rivera just showed (except for the typo), you can PROVE -b/(2a)! Why would you NOT want to do that?
Because I would rather do -b/2a than the long and complicated way.
oh ok i got it thanks
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Your welcome :D
lol
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