Question

this is another question i got wrong

Answer 1

???

Answer 2

my internet is working slow today its a theorem i got one reason wrong in it #5 is incorrect

Answer 3

Complete the proof by providing the missing reasons.
Given: CB is perpendicular to BD , DE is perpendicular to EC, CB is congruent to DE
Prove: triangle DBC is congruent to triangle CED

Answer 4

triangle DBC is congruent to triangle CED its a statement what will be its reason

Answer 5

Without knowing all the statements in the proof, it is not possible to give a reason for just one statement in the middle of the proof.

So, if you will post all the statements, then I can help, I think.

The posted question implies that the statements were given: Complete the proof by providing the missing reasons. So, I need to see whatever you were given as statements.

Answer 6

CB is perpendicular to BD , DE is perpendicular to EC, CB is congruent to DE its is a statement its reason is Given

Answer 7

<CBD and <DEC are right angle it ia statement and reason is Definition of perpendicular segments

Answer 8

<CBD is congruent to <DEC are right angle it ia statement and reason is perpendicular segments

Answer 9

CDis congruent to CD it is statement and reason is Base side congruent

Answer 10

done direstrix

Answer 11

ok

Answer 12

triangle DBC is congruent to triangle CED its a statement what will be its reason

Answer 13

I'm drawing the two triangles separately so I need a minute. I understand what you want to know.

Answer 14

ok because i have given all the satements but the says that i have to correct my statement no.5 and improve statement number 3

Answer 15

Here are the triangles marked up.

Answer 16

ok

Answer 17

SSA

Answer 18

1. CB is perpendicular to BD
DE is perpendicular to EC,
CB is congruent to DE ------------->Given

2. <CBD and <DEC are right angle -----> Perpendicular lines form right angles.
----->Definition of perpendicular lines -> OK

3. CD is congruent to CD ------> Reflexive Property of Congruence

4. triangle DBC is congruent to triangle CED --> Hypotenuse Leg Theorem