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Mathematics 22 Online
OpenStudy (waheguru):

This is a quadratics question and can someone help me graph this

OpenStudy (waheguru):

OpenStudy (abb0t):

If there's \(x^2\) it's a parabola.

OpenStudy (waheguru):

I know but How Do I graph It

OpenStudy (waheguru):

How do I make a proper table of values?

OpenStudy (waheguru):

Do I just guess or is there a way of finding good numbers for x

OpenStudy (abb0t):

You could make a table and pick some points. Say, -2,-1,0,1,2 ?

OpenStudy (waheguru):

Ill try that again but last time i did it i was not getting a curve

OpenStudy (waheguru):

The values I did were -20 -10 0 10 20

OpenStudy (waheguru):

For example For -10 i am getting -9 for y and for 10 i am getting 7.6 for y. This means the graph is not symmetrical

OpenStudy (unklerhaukus):

that just means its not symmetrical about the y axis choose x=0,20,40,60,80,100,120 you'll find it symmetrical about x=60

OpenStudy (anonymous):

you are looking at the graph

OpenStudy (waheguru):

I have another question. SO this was not symmetrical along the y axis and when I was making my table of values, I was not able to get a cororect parabola. How can I fnid out wether I should make the x values all positive or negative so I do get the symmetrical point in my table of values?

OpenStudy (goformit100):

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