Question

calculate y'. xy^4+x^2y=x+3y

Answer 1

diferentiate implicitly

Answer 2

do I have to get y by itself on one side first?

Answer 3

\(y^4 +xy^3y+2xy+x^2y'=1+3y'\) and now express \(y'\) as function of x and y

Answer 4

I don't understand.....please help

Answer 5

put one side everything that have \(y' \):
\(xy^3y' +x^2y' -3y'=1-y^4-2xy\)
now take \(y'\) as commun term:
\(y'(xy^3+x^2-3)=1-y^4-2xy\)
and just devide everything by terms in the parentesys