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The function s(t)= t^3/3-6t^2/2+5t+7 describes the position of a particle in motion. For what interval is the particle moving backwards?
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in other words, for what interval is the velocity negative!
yeah i know what it means dude... I just need to know how to get to the correct answer
take the derivative, find the critical points.|dw:1364774510905:dw|
you will get three intervals. check in what interval is the sign of the derivative negative!!! and do not call me dude.
this is so becasue the derivative of position is the velocity function.
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the derivative of the function is t^2-6t+5... i set it equal to 0 and got t=1 and t=5
|dw:1364774761880:dw| in each of those intervals, take a value for "t" and find the sign of the derivative.
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