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OpenStudy (anonymous):
Solve and check. 2^(3x) = 15
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OpenStudy (mertsj):
Take the log of both sides.
OpenStudy (anonymous):
dont understand how to get same base
OpenStudy (anonymous):
log2^(3x)=log15
OpenStudy (mertsj):
Now use loga^n=nloga
OpenStudy (anonymous):
3log2^x=log15
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OpenStudy (mertsj):
3xlog2 = log 15
OpenStudy (anonymous):
oh take x also?
OpenStudy (mertsj):
It's part of the exponent, isn't it?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
so u divide 2 and 15 but log formation?
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OpenStudy (mertsj):
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