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Mathematics 11 Online
OpenStudy (anonymous):

need help finding a formula for a series :)

OpenStudy (anonymous):

the first four terms are 3/16, 4/25, 5/36, 6/49

OpenStudy (anonymous):

Depends on the series =]

OpenStudy (anonymous):

Okay it looks like \[ a_n = \frac{n+2}{(n+3)^2} \]

OpenStudy (anonymous):

I just noticed squares in the denominator and normal number in the numerator.

OpenStudy (anonymous):

Is this the partial sum of it or is it like... the actual sequence?

OpenStudy (anonymous):

I just got it wio, and you're right thanks :)

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