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Mathematics 22 Online
OpenStudy (anonymous):

can someone check me? PLEASE HELP

OpenStudy (anonymous):

Identify which equation is a quadratic equation. i think the answer is y + x2 = (x − 2)(x + 7)

OpenStudy (anonymous):

the other choices are y = 3x + 4 y = −4x(x − 4) + 2x y + 3 = (x + 12)(x2 + 2)

OpenStudy (anonymous):

i just need to know if it is right or wrong

OpenStudy (anonymous):

It's wrong :)

OpenStudy (anonymous):

okay thanks

OpenStudy (anonymous):

would it be y + 3 = (x + 12)(x^2 + 2) ? @PeterPan

OpenStudy (anonymous):

Look, just simplify the equations and let y be on one side of the equation, and everything without y on the other. For it to be quadratic, the largest exponent of the x's should be 2 :D

OpenStudy (anonymous):

The reason this doesn't work y + x2 = (x − 2)(x + 7) Is y + x2 = x2 + 5x - 14 y = 5x - 14 Not quadratic, there is no 2-exponent.

OpenStudy (anonymous):

what about the equation i just asked about y + 3 = (x + 12)(x2 + 2) @PeterPan

OpenStudy (anonymous):

Simplify it.

OpenStudy (anonymous):

i did?

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