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Solve x = sin^-1( √(3/4)) on the interval [0,2).
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theres only one answer and its pi/3
So for x = sin^-1( -√(3/4)) is the solution -π/3? Why would someone say the solutions were π/3, 2π/3, 4π/3 and 5π/3?
@hahd And how does the interval play into it?
hmm arcsecant is a well defined function there is only one answer
satellite do you remember me? i used to be here in the beta
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old times
\[4\sin^2(x) - 3 = 0 \] This was the original equation, I had simplified it.
2pi/3 works too
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