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Mathematics 25 Online
OpenStudy (anonymous):

Solve x = sin^-1( √(3/4)) on the interval [0,2).

OpenStudy (anonymous):

theres only one answer and its pi/3

OpenStudy (anonymous):

So for x = sin^-1( -√(3/4)) is the solution -π/3? Why would someone say the solutions were π/3, 2π/3, 4π/3 and 5π/3?

OpenStudy (anonymous):

@hahd And how does the interval play into it?

OpenStudy (anonymous):

hmm arcsecant is a well defined function there is only one answer

OpenStudy (anonymous):

satellite do you remember me? i used to be here in the beta

OpenStudy (anonymous):

old times

OpenStudy (anonymous):

\[4\sin^2(x) - 3 = 0 \] This was the original equation, I had simplified it.

OpenStudy (anonymous):

2pi/3 works too

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