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Solve trig equation 0= x < 2pi rad2 sin(1/2 x)tan(1/2 x) + rad2 cos(1/2 x) = 2
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\[\LARGE \sqrt2 \sin \left( \frac{ x }{ 2} \right) \tan \left( \frac{ x }{ 2} \right) +\sqrt2 \cos \left( \frac{ x }{ 2 } \right) = 2\] ...?
yes
For simplicity, i'm replacing all the x/2 with u. So u = x/2, and i'm changing the tan into sin/cos \[\LARGE \sqrt2 \sin u \frac{ \sin u }{\cos u }+\sqrt2 \cos u = 2\] Start by multiplying both sides by cos u. Then you can use the identity sin^2 = 1 - cos^2 and you'll eventually get what looks like a quadratic equation.... i gotta leave to eat, hopefully someone will finish.
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