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OpenStudy (anonymous):
Question 6 (Multiple Choice Worth 3 points)
Solve: x + 10 = −x + 12
8
−4
4
Question 7 (Multiple Choice Worth 3 points)
Solve: 2(x + 6) − (x + 1) = 16
3
5
2
1
Question 8 (Multiple Choice Worth 3 points)
Solve: 2 − x = 13
−11
11
−15
15
Question 9 (Multiple Choice Worth 3 points)
Solve: 4(x + 1) = −12
−2
4
−3.25
−4
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OpenStudy (unklerhaukus):
\[x + 10 = −x + 12\]
take away ten form both sides , and add x to both sides
OpenStudy (unklerhaukus):
after you have done that divide both sides by two
OpenStudy (unklerhaukus):
what'd ya get?
OpenStudy (anonymous):
6
OpenStudy (unklerhaukus):
you should have an equation
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OpenStudy (anonymous):
2x=2??
OpenStudy (anonymous):
sooooooooooooooooooooooooooooo???????????????????
OpenStudy (unklerhaukus):
good. now divide both sides by two
OpenStudy (anonymous):
and i get 1
OpenStudy (unklerhaukus):
is that the third option for Question 6?
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OpenStudy (anonymous):
no its 1/2
OpenStudy (anonymous):
Light is the manifestation of a "microscopic" phenomenon.
OpenStudy (unklerhaukus):
well we can check our solution
\[x + 10 = −x + 12\]\[x=1\]
\[1 + 10 = −1 + 12\]
\[\qquad11=11\]\(\text {true}\therefore x=1, \) is a solution to \(x + 10 = −x + 12\)
OpenStudy (unklerhaukus):
Question 7\[ 2(x + 6) − (x + 1) = 16\]
first expand the brackets on the left hand side
OpenStudy (anonymous):
2x+6-(x+1=16
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OpenStudy (unklerhaukus):
try again
OpenStudy (anonymous):
2x+12 @UnkleRhaukus
OpenStudy (unklerhaukus):
that is the proper expansion of the first brackets keep going
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