Question

Find by hand the intervals where the function is increasing and decreasing. Use this information to sketch a graph. y = x^3 - 3x + 2.

Answer 1

@Mertsj can u help?

Answer 2

If I remember right that involves taking the first derivative doesn't it?

Answer 3

yes

Answer 4

If the first derivative is positive, the function is increasing on that interval
If the first derivative is negative, the function is decreasing on that interval.
Take the first derivative and write f'(x)>0. Solve that.
Then take the first derivative and write f'(x)<0. Solve that.

Answer 5

\[y'=3x^2-3\]

Answer 6

\[3x^2-3>0\]

Answer 7

\[(x-1)(x+1)>0\]