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Precalculus
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How would I go about factoring this? -3(x+2)^4-6 Do I multiply out (x+2) 4 times? Do I distribute negative 3 and then multiply it out?
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it will be the same either way but will be a lot simpler to multiply out (x+2) 4 times
Okay, Thanks!
\[-3 (x+2)^4-6\] Expanded Form: \[-3 x^4-24 x^3-72 x^2-96 x-54\]
i got \[-3x ^{4}-24x ^{3}-72x ^{2}-96x-48\]
never mind he is right its 54 because i forgot to subtract the 6
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