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convert the point (5root2,-5root2) from rectangular to polar coordinates.
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Reference Angle? Quadrant? Magnitude?
no it isn't you need \(r\) and\(\theta\) and \[r=\sqrt{(5\sqrt{2})^2+(5\sqrt{2})^2}=\sqrt{25\times 2+25\times 2}=\sqrt{100}=10\]
for \(\theta\) think about where you are over and down the same number of units |dw:1364956732437:dw|
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