Question

Just factored and got this (2x+2x) what do i do with this?

Answer 1

@amistre64
@ash2326 @Hero

Answer 2

hey

Answer 3

@Hero can you help?

Answer 4

add, since they have the same variable

Answer 5

Just add them together bro

Answer 6

lol

Answer 7

Or you could do something weird like this:

(2x + 2x)
= 2(x + x)
= 2(1 + 1)x
= 2(2)x
= 4x

Answer 8

\[4x ^{2}+6x+2\] I got it from this

Answer 9

Suggestion bro, always post the original problem you're working on

Answer 10

ok mam

Answer 11

\[(4x+2)(x+1) \]

Answer 12

Well im a sis not a bro

Answer 13

Lynncake that's not factored all the way

Answer 14

you get two values of x
\[4x+2 =0\rightarrow 4x=-2 \rightarrow x=\frac{ -1 }{ 2 }\]
\[x+1=0 \rightarrow x=-1\]

Answer 15

i got \[(2x+2) and (2x+2x)\]

Answer 16

See, that's what I mean @tomtom777, always post the original question you're working on.

Answer 17

that's not equal to \[4x^2+6x+2\]

Answer 18

That's not even close to right

Answer 19

yours equates to\[8x^2 + 8x \]

Answer 20

see mine @tomtom777

Answer 21

@Lynncake, you did not factor completely.

Answer 22

I can post the full factorization if you don't believe me.

Answer 23

im factoring my real problem is lol this\[\frac{ 4x ^{2}+6x+2 }{ 4x ^{2}-5x-6 }\]

Answer 24

i need to find the undefined

Answer 25

See, that's what you should have posted from the beginning.

Answer 26

lol

Answer 27

lol i know

Answer 28

\[\frac{ (4x+2) (x+1) }{ (4x+3)(x-2) }\]is this right? @Hero

Answer 29

For the numerator, the factorization is:

\[4x^2 + 6x + 2 \\ = 2(2x^2 + 3x + 1) \\ = 2(2x^2 + 2x + x + 1) \\ = 2(2x(x + 1) + 1(x + 1)) \\ = 2((x + 1)(2x + 1)) \\= 2(2x + 1)(x + 1)\]