Question

Stats help required

Answer 1

@wio

Answer 2

You know what the moment of a distribution is?

Answer 3

Okay i know that,

first moment=1,Second=2.3,3rd=4.5

Answer 4

Here B1=(Moment 3)^2/(Moment 2)^2

Answer 5

But i am not sure what moment about 10 means :/

Answer 6

@wio

Um,Not sure :/

Answer 7

Ahh, I figured it out.

Answer 8

The \(m\)th moment about a point \(c\) is going to be \[\Large
E[(X-c)^m] =\frac{1}{n}\sum_i^n (x_i-c)^m
\]

Answer 9

Basically you got to use algebra.

Answer 10

We know \(c = 10\) and \(n=40\)

Answer 11

The variance is the second moment about the mean.

Answer 12

The mean is the first moment about 0

Answer 13

Do you know what \(\beta\) is?