An architect built a scale model of a shopping mall. On the model, a circular fountain is 20 inches tall and 22.5 inches in diameter. If the actual fountain is to be 8 feet tall, what is its diameter? Plz help makes no sense.
You would set up a ratio equality to convert the diameter.
How would it look when set up?
First, convert the 8 feet to inches. Then the ratio of the actual height to the model height equals the actual diameter to the model diamter.
You use a fraction to get the ratio.
When it is set up, it will look like one fraction equaling another.
How do you convert the 8 feet to inches?
How many inches in one foot? Then, how many inches in 8 feet?
12.. so 8 * 12?
Yes, good so far. So, now set up the first fraction of actual height to model height.
96/ 20?
Yes. Now that fraction, which is also conceptually a ratio, will be equal to the ratio of the actual diamter to the model diameter.
so 96/20 = 22.5/ x?
We are solving for the actual diameter, so just call it "x" for now. You are close but off a bit. You have to actual on top (numerator) for both sides. On the right side, you have it in the denominator.
So, just flip over the right side.
96/ 20 = x / 22.5?
Yes, very good. You are almost done. You only have to solve for "x" now.
96 * 22.5 = 2025 / 20 x = 101.25?
I'll re-write your previous equation where it was still on track:\[\frac{ 96 }{ 20 } = \frac{ x }{ 22.5 }\]gives:\[\frac{ 96 \times 22.5 }{ 20 } = x\]
It's not 101.25
ah, think I change a number or something.. x = 108
You got it! Good job!
:)! U sure its 108.. just asking cuz its not one of my choices I have 105 but not 108
If you wrote out the problem correctly, then 108 is definitely the answer.
Yeahh I copied and paste it. Um, that's weird.
Sometimes the answer key is off because it could have a typo. That doesn't happen often, but it does happen.
Wait I don't even have 105 its 10.5.. u sure that 108 is the diameter?
108 inches.
This problems a pain lol
108 inches is 9 feet. Is one of your answers "9"?
:) Yeah!
Then you have "9" for your answer. Looks like the key is right after all, and so was my answer (both ways).
Good luck to you in all of your studies and thanks for the recognition! @LilVeroDez13
:) yes it was. thanks a lot!! would u mind helping me with one more? :)
np
Thanks! and ur welcome (:
Just start a new thread.
Ok :)
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