Question

Help?

Answer 1

@erdog82

Answer 2

I've been given this equation.... 2x2 - 4x + 1 = 0
Here is how I worked it, but I feel like I'm wrong. Help?
(4)^2-4(2)(1)
16-8
x= -8, 8

Answer 3

Sorry, it's 2x^2 - 4x + 1 = 0

Answer 4

what is your question?

Answer 5

Ok, so for this one I would use factoring.. do you know how to do that?

Answer 6

I don't recall

Answer 7

What are you asked to do?
-Factor?
-solve for x?
-Find the intercepts?

Answer 8

etc.

Answer 9

Solve Quadratic Equations

Answer 10

its when you need to do (something)(something)

Answer 11

do you know what I mean?

Answer 12

Then use the QUADRATIC EQUATION.

Answer 13

Is it when two numbers come together to equal a certain number?

Answer 14

No way, get out @some_someone you're so smart.

Answer 15

\[x = \frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a }\]

Answer 16

@Annetta_Martin Sort of..

Answer 17

2x^2 - 4x + 1 = 0

where:
a = 2
b = -4
c = 1

Answer 18

\[x = \frac{ -(-4) \pm \sqrt{(-4)^2 - 4(2)(1)} }{ 2(2) }\]

Answer 19

general form of quadratic equation is ax^2+bx+c=0
put values of a, b & c in quadratic formula:
x = \[\frac{-b \pm \sqrt{b ^{2}-4ac}}{2a } \]

Answer 20

exactly,
\[ax^2+bx+c=0\]
\[2x^2 - 4x + 1 = 0\]

Answer 21

Does x= +/- 24?

Answer 22

For the quadratic equation,
\[2 x^2-4 x+1 = 0\]
The solutions you have gotten are not correct.

Answer 23

solution =(1.7 , 0.3 ) i think this will be the solution

Answer 24

\[x = \frac{ 4 \pm \sqrt{16 - 8} }{ 4 }\]
\[x = \frac{ 4 \pm \sqrt{8} }{ 4 }\]

Answer 25

This follows up with what I did earlier.

Answer 26

x=-2.84, 2.84?

Answer 27

Annetta can you show the steps you've done ?

Answer 28

x=-(-4)+/-√(-4)^2-4(2)(1) / 2(2)
x=4+/-√16-8 / 4
x= 4+/-√8 / 4
x= 4+/-2.83 / 4
x=-2.84, 2.84

Answer 29

last step will go like this
(4+ 2.83)/4 and (4-2.83)/4
x= 1.707 and 0.3

Answer 30

\[x = \frac{ 4 + \sqrt{8} }{ 4 } \]

and

\[x = \frac{ 4 - \sqrt{8} }{ 4 } \]

Answer 31

Oh, I multiplied it...

Answer 32

lol its ok we learn from our mistakes :)
hope you get it now