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Help!!! 3(5)^2x-3 =6
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\[3\times 5^{2x}-3=6\] \[3\times 5^{2x}=9\] \[5^{2x}=3\] is a start
unless i read it wrong is it \[3\times 5^{2x-3}=9\]?
if it is the latter, then start with \[5^{2x-3}=3\] which one might it be?
The first one is correct the one you started
Actually it's the latter
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ok so now it looks like we want it \[5^{2x}=3\] then\[b^x=A\iff x=\frac{\ln(A)}{\ln(b)}\] you have \[5^{2x}=3\] so \[2x=\frac{\ln(3)}{\ln(5)}\] making \[x=\frac{\ln(3)}{2\ln(5)}\]
Except it equals6
I'm sorry
is it this \[3\times 5^{2x-3}=9\]
Yeah but it equals 6 instead of 9
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\[3\times 5^{2x-3}=6\]?
divide by 3, get \[5^{2x-3}=2\]
then \[2x-3=\frac{\ln(2)}{\ln(5)}\]
add three and divide by 2 to solve for \(x\)
Okay Is the answer x=1.71
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