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OpenStudy (dan815):
hi
OpenStudy (anonymous):
|dw:1365047184256:dw|
OpenStudy (anonymous):
heeey
OpenStudy (dan815):
wat is that 120 degrees
OpenStudy (dan815):
is there some symmetry i shud know like that point B is on the center of the bottom
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OpenStudy (anonymous):
in the drawing? its the angle but my answer is also 120 because its b has to be half of acb
OpenStudy (anonymous):
um i thinkk i tried my best to copy the pic lol
OpenStudy (anonymous):
Just looking at it the arc AB is about a third of the circumference of the the circle 360/3=120. Sounds legit.
OpenStudy (anonymous):
If The triange ABC is equilateral then I know I'm right and so are you
OpenStudy (anonymous):
yeah and the theorem says to do it like that i think its right just wanted to make sure :)
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OpenStudy (anonymous):
what theorem?
OpenStudy (anonymous):
theorem 10.11
OpenStudy (anonymous):
Oh yeah that one .... of course....how could I forget theorem 10.11 how embarrassing....
Seriously wtf is theorem 10.11 I don't have your book you know.
OpenStudy (anonymous):
smh nvm i know im right u dnt need to be rude.. and thats what its called by the way thanks for all ure help
OpenStudy (anonymous):
You're welcome.
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OpenStudy (dan815):
oh i see so i join abc its an equilateral triangle right
OpenStudy (anonymous):
it doesnt say its equilateral i just did it by following the theorem