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Mathematics 19 Online
OpenStudy (anonymous):

In a batch of 890 calculators, 12 were found to be defective. What is the probability that a calculator chosen at random will be defective? Write the probability as a percent. Round to the nearest tenth of a percent if necessary.

Directrix (directrix):

P(bad calc) = 12/890 --> That is what I think. @some_someone

OpenStudy (anonymous):

Okaii I found my mistake.

OpenStudy (anonymous):

sorry about that.

OpenStudy (anonymous):

12 in 890 are defective

Directrix (directrix):

Did you get .0134 as the decimal approx?

OpenStudy (anonymous):

that is 12/890

OpenStudy (anonymous):

which is approximately 0.013483146

OpenStudy (anonymous):

Yes sir @Directrix I agree :)

OpenStudy (kropot72):

Reminder: The answer must be converted to a percentage.

OpenStudy (anonymous):

converting to percent multiply by 100 giving 1.348314607

OpenStudy (anonymous):

I GOT IT THANKS PEEPS

OpenStudy (anonymous):

yw

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