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In a batch of 890 calculators, 12 were found to be defective. What is the probability that a calculator chosen at random will be defective? Write the probability as a percent. Round to the nearest tenth of a percent if necessary.
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P(bad calc) = 12/890 --> That is what I think. @some_someone
Okaii I found my mistake.
sorry about that.
12 in 890 are defective
Did you get .0134 as the decimal approx?
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that is 12/890
which is approximately 0.013483146
Yes sir @Directrix I agree :)
Reminder: The answer must be converted to a percentage.
converting to percent multiply by 100 giving 1.348314607
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I GOT IT THANKS PEEPS
yw
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