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how do you do this step by step: 3/5(k-2)-1/4(2k-7)<3
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and then i have one more for you to look at
are the (k-2) and (2k-7) both in the denominators ?
|dw:1365095821317:dw|
okay here is the last one
\[4x-3\div6+2\ge2x-1\div12\]
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|dw:1365096307265:dw|
okay now i see how you are doing this cause i have to practice this. Thank you for your help
Welcome:)
@krissywatts remember when u cancel "-" on both sides inequality changes
okay i will try
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example - 2x > -6 2x < 6 x < 3
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yes
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