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8^x=1/128
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solve the equation analytically.
\[xln8=\ln(1)-\ln(128)\]
that's right, and divide by ln(8)
is it \[x= \frac{ \ln 127 }{ \ln 8 }\]
\[(2^{3})^{x}=2^{-7}\] For some reason that looks like that might help. But don't see how lol.
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@the answer is supposed to be x=-7/3
Now I see how it helps.
@radar does this mean the single ln(1) doesnt matter then ?
Isn't the ln1 a zero?
lol.. i am barely learning it i thought i would have to subtract ln(1)-ln(128) but your equation was much more helpful thanks
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I was attempting to show a solution by getting around logs (because I am easily confused with them) lol
ha thanks it worked
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