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Mathematics 7 Online
OpenStudy (anonymous):

2^(x^(3)-x)=1

OpenStudy (anonymous):

\[2^{x ^{3}-x}=1\]

OpenStudy (anonymous):

how about the ones where an exponent has an exponent

OpenStudy (anonymous):

solve the equation analytically.

OpenStudy (anonymous):

solved it... how about \[3^{7x}=81^{4-2x}\]

OpenStudy (anonymous):

\[7x \log 3= 81^{4-2x}\]

OpenStudy (anonymous):

can i write this like this

OpenStudy (anonymous):

\[3^{4(4-2x)}\]

OpenStudy (anonymous):

i get the same logs and i can just write 7x=4-2x

OpenStudy (anonymous):

5x=4 x=4/5

OpenStudy (anonymous):

i got it wrong @radar

OpenStudy (anonymous):

its supposed to be x=16/15

OpenStudy (anonymous):

i gotttttt ittttt aaaayeeeee!!!!!!

OpenStudy (radar):

Sorry I lead you astray, but glad you worked it out, did you use logs?

OpenStudy (radar):

Oh!, never mind this looks like a different problem. I am studying it now.

OpenStudy (radar):

|dw:1365101159216:dw|

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