Question

Solve: (3k + 11)^2 = 7
here's what I have so fare, please check and/or correct:
(3k + 11)(3k + 11) = 7
9k^2 + 33k + 33k + 121 = 7
9k^2 + 66k = 7 - 121
9k^2 + 66k = -1124

Answer 1

Just leave it in its original form and take the square root of both sides.

Answer 2

You subtracted wrong. 7 - 121 = -114... Then get it back to the other side and factor. All numbers are divisible by 3 so start there

Answer 3

Answers are -4.548584 and -2.78475

Answer 4

okay so answer the first respons i would : the squareroot of 3k + 11 = the square root of 7?

Answer 5

Yes. Now you're on the right track. Just remember that there are 2 square roots of 7...the positive one and the negative one.

Answer 6

I should look like this:
\[3k+11=\pm \sqrt{7}\]

Answer 7

Now subtract 11 from both sides:

Answer 8

divide by 3 on both sides?

Answer 9

\[3k=-11\pm \sqrt{7}\]

Answer 10

Now divide by 3. yes.

Answer 11

so the answer is k = -11 +- the square root of 7/ 3

Answer 12

yes

Answer 13

\[k=\frac{-11\pm \sqrt{7}}{3}\]

Answer 14

okay cool thank u

Answer 15

yw