Conditional Probability: A five digit number is formed from the digits 1, 2, 3, 4, and 5. What is the probability that the number ends in the digits 52, given that it is even?
is it that it ends in the digits 5 and 2, or that it ends in either 5 or 2?
i think 5 and 2 but them the second part says given that it is even but if it is 5 and 2 wouldn't it always be even?
if it means 5 or 2, then: we have two events, Event B is that is even and has probability of 2/5 Event A is that it ends in 5 or 2, and has a probability of 2/5. We need Event A given Event B. Formula is : probability of a interesecting b over probability b
ok
intersection of a and b has a probability of 1/5
i will just use that
oh ok
because of the five numbers, only one of them is in both events.
the five right?, or no?
well the number 5 right? because its in both
one event is that it is 5 or 2, another is that it is even. 5 is not even!
ohh wow, my bad ok
so probability of a interesecting b over probability b will be: (1/5) / (2/5) = .2/.4 = 1/2 or 0.5
ok thank you, i think i get it now
would you help me on another problem or are you busy?
i can try
okay so the instructions say. A card is chosen from a standard deck of cards. Find the probability that the card is black. The question says: P(4)
how many cards are in a deck? and what is p4?
52 and i think card #4 in a deck
becuase other questions say P(facecard) or P(jack or ten)
does it use the word given in the question (e.g. black given that it is a 4) or just ask for the probability of a black 4?
oh yes it does i wrote it wrong: A card is chosen from a standard deck of cards. Find the probability Given that the card is black
ok, that is very important in probability questions. always look for it.
alright
how many options in a deck, sorry :)
1-10, + jack, queen and king? = 1/13?
whoops: the probability of being black is 1/2, the probability of being a 4 is 1/13
There are 52 cards in a standard deck of cards. There are 26 black cards and 26 red cards in a deck. There are 4 suits (Spades (black), Hearts (red), Diamonds (red), Clubs (black)), each consists of 13 cards, and they are Ace, King, Queen, Jack, 10, 9, 8, 7, 6, 5, 4, 3, and 2 in a deck. There are 4 for every each type of cards (Ace, King, Queen, Jack, 10, 9, 8, 7, 6, 5, 4, 3, and 2) in a deck. There are usually 2 Jokers in a deck.
so probability of a 4 in a suit is 1/13?
now, we need probability of 4 given black. Our formula is probability of a interesecting b over probability b
probability b is 1/2
yea i believe so
ok, and probability a intersecting b is the probability of getting a black and a four out of 52. which is 2/52 because there are are 4 number fours, and two are red.
so probability of a interesecting b over probability b is (2/52)/(1/2)
which gives me 1/13 ok thank you, would you mind helping me on another??, sorry
ill watch u do it.
ok i will try that out
With the same intrustions I have of :A card is chosen from a standard deck of cards. Find the probability Given that the card is black. And the question says P(6 of clubs)
so i know that i need 6 clubs out of the deck
what are the two events?
i think event B is 6/52 and event A is 4/52?
6 because of the 6 clubs
name the events. event a is that ... will occur. event b is that ... will occur. then get the probabilities.
ok let me try so Event A is that 6 clubs out of 52 cards will occur?
no, its that you will get the six of clubs.
Event B is that 26 black cards out of 52 cards will occur?
event a is that when you pick a card you will get the six of clubs. event b is that when you pick a card it will be black.
oh and a club has 13 cards
now what is the probability of event a, and what is the probability of event b?
how do you know which event is A or B?
good question. that is arbitrary, you can decide which is which, as long as you stick with it.
the probability of event A is 1/52. Since it is a 6 of clubs that is just one card right?
oh ok, i didnt know that
yep!
(just lookout for when the question has already told you which is a and which is b)
ok, the probability of b is?
ok and event B is that 2/52, since yea two of the 4's are red
try again. what are the chances of pickng a black card out of a deck?
event a is that when you pick a card you will get the six of clubs. event b is that when you pick a card it will be black.
26 black cards in the deck. so 26/52
yep or 1/2
alright
now what is a intersecting b - in other words, how many cards meet both criteria
divide both of the fractions right? event A over B
how man cards are both black and the six of clubs out of the fifty two cards?
1
bingo.
1/52?
now do we need a given b or b given a?
1/52 is correct
Find the probability Given that the card is black was the question. event a is that when you pick a card you will get the six of clubs. event b is that when you pick a card it will be black. so we need a given b.
thank youuu! would you like to watch me do 3 more?? :), its my homework and this lesson confuses me but I think I am learning a lot right now
oh wait the problem isn't finished or did we finish it?
not yet
we have so far probability a, probability b, and we need probability a given b.
and we also have probability a intersecting b.
ohh ok, lets see how would i start to find that?
formula...
(always remember that probability of a intersecting b is different to a given b)
the formula would then be probability A intersecting B over B?
exactly. pr(a intersecting b) over pr(b)
okay
so what was pr(b)? (probability of picking a black card)? and waht was pr (a intersecting b)? (probability of picking a card both black and 6 of clubs)?
is it 1/2 * 1/52 all over 1/2
its (1/52)/(1/2)
so the 1/2 cancels
oh ok ok
so 1/26 would be my answer?
showing that it is a 6 of clubs and that it is one of the black cards
yes.
yess ok
i have to go, but a small tip if i may, to really understand probability and be good at it, its worth getting clear the difference between pr(a given b) and pr(a intersecting b), and understanding what they mean. try and understand whats going on in each question, and not just use the formulas.
ok no problem thanks a million. I understood this more than being in my class. and you helped me for a while. I will review this chat for help if I am stuck. And ok I will try to do that. Thank Youu!
send me a message if u want help, and ill get back to you if i have time. (no promises)
good luck. probability takes a bit of time to get the hang of.
alrighty, thats fine
i want to understand it for the final so I will do the practice
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