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Identify the holes in the graph of the function: f(x)=x^4/x
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Make the denominator zero (0).
y = x^4/x y = x³ where x ≠ 0. The graph has a hole at the point with coordinates (0,0).
Thanks
I have a quick question can the sixth roots of 1 be just plain 1 or -+1?
1 has six sixth roots. Two of those six roots are 1 and -1. So, in answer to your question, >>can the sixth roots of 1 be just plain 1 or -+1? NO.
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okay
so If I have this question: Find all real roots: sixth roots of 1. and I have options of 1, -+1, 0, and no real roots. Can I pick the second option?
The other four are complex but not real. Look at them.
These two are the only real roots: -+1--> 1 and - 1
okay
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Got it. Thank you so much!
Glad to help.
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