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Proportion: a projector is shining an image on a screen 'd' metres away. the brightness of the image 'B' varies inversly as the square of the distance. when d=5 and B=40 calculate B when d=3.7 pretty easy question but would it be B=k/sqrtD or B=k/D^2 ? Thanks
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so is the equation: \[B=\frac{ k }{ d^{2} }\] or \[B=\frac{ k }{ \sqrt{d} }\]
It's the first equation.
i think the second one is correct
haha whose right?
sorry rav is right
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okay thanks
b is as square
it's not math it's grammar , square refers to b
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